J.R. S. answered 11/14/17
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(1) Mn before the reaction is 7+ as detailed by LaRita. Carbon before the reaction has an oxidation state of 3+.
After the reaction, Mn has an oxidation state of 2+ and C has an oxidation state of 4+.
(2) MnO4- + 8H+ + 5e- ==> Mn2+ + 4H2O reduction half reaction
C2O42- ==> 2CO2 + 2e- oxidation half reaction
Multiply reduction half reaction by 2 and oxidation half reaction by 5 to balance electrons and cancel electrons
2MnO4- + 16H+ + 5C2O42- ===> 2Mn2+ + 8H2O + 10CO2 Balanced for mass and charge