A 5kg wooden box is oulled along the floor at a constant speed, with a force of 70N at an angle of 25° to the horizontal.

Question

a) draw free body diagram of all forces acting on the box

b) calcuate the magnitude of the support force from the floor and the friction force.

Answer 1

Support force from floor:

 

F + (70 N)(sin25°) = mg = (5 kg)(9.8 m/s²) = 49 N

 

F = (49 - 70sin25°) N ≅ 19.42 N

 

Friction force:

 

f = (70 N)cos25° ≅ 63.44 N

 

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