A rectangle has an area of 50 inches squared. The length is twice the width. Use an algebraic equation and find the dimensions of this rectangle

Question

Use an algebraic equation and find the dimensions of this rectangle.

Answer 1

50 sq inch= Area of a rectangle suppose width = w inches, length= 2w inches area of a rectangle= 2w*w 50= 2w*w 25=W.W W= 5 inches, 2W= 10 inches

Answer 2

A = Lw

 

50 = (2w)*w

 

50 = 2*w^2

 

25 = w^2

 

w = 5 <--- positive square root, as negative measures not allowed

 

Length is 2*5=10 and width is 5