Devon P.

asked • 11/09/17

If h(x) = 1+3x and k(x) = x+2

Calculate (i) hk(x) (ii) hk(4) (iii) (hk)^-1(x) (iv) The value of x, when hk(x) = 0

1 Expert Answer

By:

Kenneth S. answered • 11/09/17

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i)  hk(x)  should be written as h(x)k(x) if you mean to multiply two quantities; or should be written as (hok)(x) if you intended to do composition of functions.  

Since your notation is unclear, I request that you clarify these problems (all iv of them), resubmit, and someone will come along to help.
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Devon P.

Thank you so much sir for responding. What I am doing is the composition of functions
 
Questions rewritten 
(i)    (hok) (x) 
(ii)   (hok) (4)
(iii)  (hok) ^-1(x)
(iv)  The value of x, when (hok)(x) = 0 
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11/09/17

Kenneth S.

h(x) = 1+3x and k(x) = x+2
 
(i) (hok) (x) means h(  k(x) ) so it's 1 + 3 (x+2) which is 3x + 7.
 
ii) just use the above result, substituting 4 in place of x, now.
 
iii) just do the usual INVERSE PROCEDURE on the result that I supplied in i).  That is, interchange x & y, then solve for y, and then call it (hok) -1(x), the inverse of the composition of h with k.
 
All right?
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11/09/17

Devon P.

Thank you guys so, so much... This really helped and God bless u :-)
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11/09/17

Kenneth S.

Thanks for the feedback; glad I could help.
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11/09/17

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