You MUST write a balanced equation for this reaction:
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
Next, calculate moles NaOH used:
0.760 L NaOH x 0.300 moles/L = 0.228 moles (assuming you meant 0.300 M and not 0.300 m. See below)
Next, note the mole ratio in the balanced equation between NaOH and H2SO4. It is 2:1
Calculate moles H2SO4 present using this ratio:
0.228 moles NaOH x 1 mole H2SO4/2 moles NaOH = 0.114 moles H2SO4 neutralized.
NOTE: There is a significant difference between 0.3 m and 0.3 M. The former means 0.3 moles/kg of solvent and the latter means 0.3 moles/L of solution. Be careful which one you use. If the problem REALLY said 0.3 m, you would have to know the density of the NaOH to solve the problem.