Standard form polynomial 4, -4, -2

Question

4 , -4,-2

Answer 1

Is your question that you want us to write a polynomial with zeros at 4, -4 and -2?

If so,

x = 4, x = -4, and x = -2

x - 4 = 0, x + 4 = 0, x + 2 = 0

(x-4)(x+4)(x+2) = 0

(x² - 16)(x + 2) = 0

x³ + 2x² - 16x - 32 = 0 

Answer 2

f(x) = (x-4)(x+4)(x+2)

 

Multiply it out to put it into standard form (ax³ + bx² + cx + d).