David S.

asked • 11/05/17# How can I figure this problem out?

So my problem on my precalculus homework is “Rodney shoots a basket at 6.5ft above the ground. It’s initial velocity is 25 feet per second. How many seconds after shooting does the ball go through the hoop?”

im so confused

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## 1 Expert Answer

Arturo O. answered • 11/05/17

Experienced Physics Teacher for Physics Tutoring

h(t) = (-1/2)32t

^{2}+ 25t + 6.5 = -16t

^{2}+ 25t + 6.5

h in feet, t in seconds

When it reaches a height H,

H = -16t

^{2}+ 25t + 6.5

-16t

^{2}+ 25t + (6.5 - H) = 0

Solve this quadratic equation for t. I should give a negative and a positive solution, Since t starts at t = 0, the answer is the positive solution. Plug in the correct value of H and solve.

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Arturo O.

^{2}+ 25t + 6.5 = -16t^{2}+ 25t + 6.5^{2}+ 25t + (6.5 - H) = 011/05/17