Philip P. answered 11/05/17
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This is like a spinner problem, similar to the "Wheel of Fortune". Let's assume that the wheel is divided into 360 degrees (we'll assume alignment within one degree). So imagine four Wheel of Fortune spinners. Spin one of them and see where it stops. Now spin the other three. The odds that one of the other three would end up in the same position is 3/360 = 1/120. The odds that two end up in the same position as the first are (3/360)(2/360) = 1/21,600. The odds of all four wheels aligning is (3/360)(2/360)(1/360) = 1/7,776,000.