Arturo O. answered 11/02/17
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I assume the angle is 60°, not 600.
The 2 forces are perpendicular, so you can call one Fx and the other Fy. I will call Fx the one that points 60° from the resultant. The following relations apply:
√(Fx2 + Fy2) = 100 N
Fx = (100 N)cos60° = 50 N
Fy = (100 N)sin60° ≅ 86.60 N