Arturo O. answered • 10/26/17

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y'' - 9y' + 20 = 0

The characteristic equation is

λ

^{2}- 9λ + 20 = 0(λ - 4)(λ - 5) = 20

λ = 4 or 5

General solution:

y(t) = ae

^{4t}+ be^{5t}I am not sure what you mean by y

_{1 }and y_{2}. Generally, the initial conditions are specified for the entire solution, asy(0) = ?

y'(0) = ?

These 2 initial conditions give you 2 equations in 2 unknowns a and b, which you can use to solve for a and b once you have the general solution.

Megan L.

10/26/17