Scalar product

Question

The power developed by a certain engine is a function of time according to


P = 2 + 3t2 + 4t3

where the units are SI. The work done by the engine in the interval from t = 0 to t = 2 s is?

Answer 1

P = dW/dt ⇒

 

W = ∫P(t)dt

 

W_0→2 = ∫₀² (2 + 3t² + 4t³)dt = (2t + t³ + t⁴)|₀² = ?

 

You should be able to finish from here.