PHYSICS QUESTION! PLEASE HELP

Question

A conductor in a train travelling at 12.0 km/h [N] relative to the ground while he walks across the aisle at 5.0 km/h [E] relative to the train. What is his velocity relative to the ground?

Answer 1

v = √(v_N² + v_E²) = √(12.0² + 5.0²) km/h = 13 km/h

 

θ = tan^-1(v_N/v_E) = tan^-1(12.0/5.0) = 67.38°

 

The velocity is 13 km/h, at a direction of 67.38° north of east.