A car enters the freeway with a speed of 6.6 m/s and accelerates uniformly for 4.7 km in 3.8 min. How fast (in m/s) is the car moving after this time?

Question

A car enters the freeway with a speed of 6.6 m/s and accelerates uniformly for 4.7 km in 3.8 min. How fast (in m/s) is the car moving after this time?

Answer 1

Hi Anna

Initial speed = 6.6 m/s = u

Final speed  v= ?

S = Distance moved = 4700 m , t= 3.8*60 sec

time t= 3.8*60 sec

V = 6.6 + a* 3.8*60.... Eq 1

S= ut + 1/2 at²

 

4700 = 6.6 * 3.8*60 +1/2 a * 3.8*60*3.8*60..... Eq 2

From these two Equations get V