Find the displacement after 4.15 s. (physics)

Question

An automobile with an initial speed of 3.89 m/s accelerates uniformly at the rate of 3.55 m/s2. Find the displacement after 4.15 s.

Answer 1

d = v₀·t + at²/2

• d = distance
• v₀ = initial velocity = 3.89 m/s
• t = time = 4.15 s
• a = acceleration = 3.55 m/s²

 

Plug in the numbers and compute the answer.