Victoria V. answered 10/20/17
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20+years teaching PreCalculus & all Surrounding Topics
Just like in the last problem you asked,
Find the factors using synthetic division.
The only options are ±(4/1), ±(4/2), ±(4/4) or ±4, ±2, ±1
Try all of these and see which give you zeros for remainders.
Once you find one, factor the remaining quadratic.
Using x = -2: you find a remainder of 0 and a reduced polynomial of 2x2-2 = 0
With x=-2 as a root, the factor is (x+2)
With 2x2- 2=0, factor out a 2 and find 2(x2-1) which factors into 2(x-1)(x+1)
And so these are your linear factors.
As a product: f(x)=2(x+2)(x+1)(x-1)