For a uniform acceleration, d = (1/2)at2
- d = distance = 156 m
- a = acceleration = 1.1 m/s2
- t = time
Solving for time (t):
t = √(2d/a)
t = √(2·156/1.1)
t = 16.8 sec
The car accelerates for 16.8 seconds. It's final speed will be:
v = v0 + a·t
- v0 = starting speed = 6.4 m/s
- a = acceleration = 1.1 m/s2
- t = time = 16.8 sec
Plug in the numbers and compute the answer.
Sam N.
10/19/17