a car drives off the edge of a cliff that is 106m high. The police say the point of impact is 56.0m from the base of the cliff. How long does the car fall?

Question

We have been given these equations. t=√(2d_x/g) and t=d_x/v_x

Answer 1

The time it will take the car to fall 106 m is:

 

t = √(2h/g), where:

• t = time
• h = height = 106 m
• g = acceleration due to gravity = 9.8 m/s²

 

t = √(2(106)/9.8) = 4.65 sec

 

Ignoring friction, the car's horizontal speed as it drove off the cliff is:

 

v_x = d_x/t, where:

• v_x = horizontal speed
• d_x = distance car went horizontally in 4.65 sec = 56 m
• t = time = 4.65 sec

 

v_x = 56/4.65 = ______ m/s