the length of a rectangle is five less than twice its width. if the perimeter of the rectangle is 56 inches find its dimensions

Question

please show the work 

Answer 1

Let l = length, w = width

 

l = 2w - 5     (1)

2l + 2w = 56     (2)

 

Plugging equation 1 into equation 2 gives:

2(2w - 5) + 2w = 56

 

Now, solve for w.

4w - 10 + 2w = 56

6w = 66

w = 11

 

Finally, we can use the width to determine the length.

l = 2w - 5 = 2(11) - 5

l = 17