For the quadratic f(x) = 1 − 6x − x^2

Question

(a) Express f(x) in standard form

 

(c)find its maximum or minimum value.

Answer 1

f(x) = 1 - 6x - x²

f(x) = -x² - 6x + 1

f(x) = -(x² + 6x) + 1

f(x) = -(x² + 6x + 9) + 1 + 9

f(x) = -(x + 3) + 10

 

This is vertex form. It has the maximum.