In a​ five-card poker​ hand, what is the probability of being dealt exactly one three

Question

 this is my question

Answer 1

To get exactly one three: can be done in 4C1 ways.

To deal any of the remaining 48 non-threes can be done in 48C4 ways.

 

The number of hands of this precise type is the product of the above two numbers.

 

For the probability of this event, the denominator is the usual 52C5 number.