rate of the slower train and faster train

Question

Two trains leave towns
744mi
apart at the same time and travel toward each other. One train travels
10

/mih
slower than the other. If they meet in
4
hours, what is the rate of each train?

Answer 1

d_fast = 4r

d_slow = 4(r - 10)

 

Sum of distance equals 744

 

4r + 4(r - 10) = 744

 

Can you solve for r and answer?