tan3x - tan2x- tanx=tan(2x+x)-tan2x-tanx=(tan2x+tanx)/(1-tan2xtanx)-(tan2x+tanx)
=(tan2x+tanx)(1/(1-tan2xtanx)-1)=(tan2x+tanx)(1-(1-tan2xtanx))/(1-tan2xtanx)=(tan2x+tanx)(tan2xtanx/(1-tan2xtanx)=[(tan2x+tanx)/(1-tan2xtanx)]tan2xtanx=tan3xtan2xtanx
Tony S.
asked • 07/24/14How to prove this identity
tan3x - tan2x- tanx = tan3xtan2xtanx
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