Inactive Tutor answered 05/13/13
Tutor
New to Wyzant
Take reciprocals,
sin2(x/2) = cos(x)/2
=> 2sin2(x/2) = cos(x)
=> 1-cos(x) = cos(x)
=> cos(x) = 1/2
=> x = pi/3, 5pi/3 on [0, 2pi).
Kira L.
asked 05/13/13csc2(x/2)=2sec(x)
Please help me solve for x.
Inactive Tutor answered 05/13/13
Take reciprocals,
sin2(x/2) = cos(x)/2
=> 2sin2(x/2) = cos(x)
=> 1-cos(x) = cos(x)
=> cos(x) = 1/2
=> x = pi/3, 5pi/3 on [0, 2pi).
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