1. If cos x = -cos(π/6) and π/2<x<π, find the value of x.
Arturo O.
answered • 09/06/17
Experienced Physics Teacher for Physics Tutoring
The condition
π/2 < x < π
puts x in Quadrant II.
You can use the identity
cos(π - a) = -cos(a)
a = π/6
cos(π - π/6) = -cos(π/6)
π - π/6 = 5π/6
cos(5π/6) = -cos(π/6)
x = 5π/6
x is in Quadrant II.
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