seven order pairs for y=x^2-8

Question

I need to know what seven ordered pairs are for this equation. Thank you!

Answer 1

To find an ordered pair plug in a value

for x and solve for y

 

x     | y = x²-8    |   pair

-----|------------- |--------

-3   |  9-8=1       | (-3, 1)

-2   | 4-8= -4      | (-2, -4)

-1   | 1-8=-7       | (-1, -7)

 0.  | 0-8=-8       |  (0, -8)

 1   | 1-8=-7       |  (1, -7)

 2   |                   |

 3   |                   |

 

Just finish the last couple of calculations