Find the real solution 2x^2=9-5x

Question

Use the quadratic formula 

Answer 1

2x² = 9 - 5x

 

2x² + 5x - 9 = 0

 

a = 2

b = 5

c = -9

 

D = b² - 4ac = 5² - 4(2)(-9) = 97

 

x = (-b ± √D) / (2a)

 

Since D > 0, there are 2 real solutions.  You should be able to finish from here.

Answer 2

2x² + 5x - 9 = 0

 

x = [-5 ± √(5² - 4(2)(-9))] / (2(2))

 

   = [-5 ± √97] / 4

 

Answer 3

first, write this quadratic equation in standard form.

 

2x² + 5x - 9 = 0

 

 

Then just use the formula that is laid out in your textbook appendix.