i don't know how to do this i need someone to explain me how to do it?

Question

2/3(2x-5)=7/3(4x+3)

Answer 1

(4/3)X - (10/3) = (28/3)X + (21/3)  <--- DISTRIBUTIVE

 

0 = (28/3)X - (4/3)X + (21/3) + 10/3  <--- moves everything to the right side, so as to get X's positive;

                                                                   signs change

 

0 = (24/3)X + 31/3  <--- combines like terms

 

-31/3 = 8X

 

X = (-31/3)/8 = (-31/3) * (1/8) = -31/24 <--- WHEN DIVIDING FRACTIONS: KFC --> keep, change, flip

 

CHECK:

Left side:

 (2/3) (   2*(-31/24) - 5 ) =

 (2/3) ( (-31/12) - 5 ) =          <---- 2 cancels 24

 (2/3) (  ( -31/12) - 60/12) =   <--- common denominators

(2/3) ( -91/12) =

(1/3) ( -91/6) =         <--- 2 cancels 12

-91/18

 

Right side:

 

 (7/3) (  4 ( -31/24) + 3) =

(7/3) (  -31/6 + 3) =           <--- 4 cancels 24

(7/3) ( -31/6 + 18/6 ) =      <--- common denominator

(7/3) ( -13/6) =      

-91/18

 

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Like the other problem I did for you, Nany,

you MUST check the answers to these algebra

problems ESPECIALLy if the answer is a fraction.

 

Answer 2

The distributive property is used to solve these:

(2/3 * 2x)+(2/3 * -5) = (7/3 * 4x)+(7/3 *3)

4/3x - 10/3 = 28/3x + 21/3

 

Solve for x.

(Using the result above, begin with -4/3x to both sides.)

-10/3 = 24/3x + 21/3

(-21/3 to both sides.)

-31/3 = 24/3x

(Converting the x-variable fraction to a whole number = 8), so,

8x = -31/3

(Divide both sides by 8)

-31/3 ÷ 8 is the same as

-31/3 * 1/8, so

x = -31/24

Answer 3

CLEAR FRACTIONS before distributing. This question was submitted by you and has been answered.