three consecutive odd numbers that equal 105

Question

this math is way too hard and i need help so anybody heko

Answer 1

Andy gave you a good solution.  I just want to point out two other ways to solve the problem.  You could start with the higher number.  Call it n.  Then

 

n + (n - 2) + (n - 4) = 105

3n - 6 = 105

3n = 111

n = 37

 

Then the 3 numbers are

 

37

37 - 2 = 35

37 - 4 = 33

 

You could also start with the number in the middle.  Call it m.

 

m + (m - 2) + (m + 2) = 105

 

3m = 105

m = 35

 

The 3 numbers are

 

35

35 - 2 = 33

35 + 2 = 37

 

Same answer, just slightly different approaches to solve the problem.

Answer 2

x: 1st odd integer

x+2 : 2nd odd integer

x+4: 3rd odd integer

 

x + (x+2) + (x+4) = 105

 

3x + 6 = 105

 

3x = 99

x = 33

 

33, 35, and 37