Graph the function f(x)=(sqrt x+2)+3 . To do so, graph the leftmost point and three additional points

Question

How can you figure out the points when the x is a square root

Answer 1

Hi Meira, I am not sure where the parenthesis belong. I am using the following formation:

 

f(x) = sqrt(x + 2) + 3

 

If this is incorrect, you can still follow the same steps.

 

I want to plot four points. Let x = 1, 2, 3, and 4.

 

Substitute for x each of the four values, which results in four values for f(x).

 

The value of sqrt(x + 2) is zero when x = -2. This is the left most point.

 

x = -2, f(x) = sqrt(-2 + 2) + 3, f(x) = 3

 

x = 0, f(x) = sqrt(0 + 2) + 3, f(x) = 4.14

 

x = 3, f(x) = sqrt(3 + 2) + 3, f(x) = 5.24

 

x = 4, f(x) = sqrt(4 + 2) + 3, f(x) = 5.45

 

Questions?

Answer 2

f(x) = √(x+2) + 3.  The graph of this function can be obtained by first translating the graph of y = √x two units to the left and then translating that graph three units upward.

 

Points on the graph of y = √x :   (0,0)  (leftmost point) , (1,1), (4,2), (9,3)

 

Corresponding points on the graph of f(x) = √(x+2) + 3:  (-2,3) (leftmost),  (-1, 4), (2,5), (7,6)