Arthur D. answered 07/09/14
Tutor
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Forty Year Educator: Classroom, Summer School, Substitute, Tutor
2x-3y=-7
3x+4y=15
Multiply the first equation by 3 and the second equation by 2.
3(2x-3y)=3(-7)
2(3x+4y)=2(15)
6x-9y=-21
6x+8y=30
Subtract the second equation from the first equation.
-17y=-51
y=(-51)/(-17)
y=3
Substitute 3 for y in either original equation.
2x-3(3)=-7
2x-9=-7
2x=9-7
2x=2
x=1
x=1, y=3