Arturo O. answered • 08/12/17
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∑k=15 (k2 + k) = (12 + 1) + (22 + 2) + (32 + 3) + (42 + 4) + (52 + 5)
= 2 + 6 + 12 + 20 + 30 = 70
Freddy G.
asked • 08/11/17evaluate and simplify
5
∑(k^2 +k)
k=1
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= 2 + 6 + 12 + 20 + 30 = 70
= (12 + 1) + (22 + 2) + (32 + 3) + (42 + 4) + (52 + 5)
= 2 + 6 + 12 + 18 + 30
= 68
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