The notebook cost 98 cents more than a pencil. Represent the cost of half a dozen pencils and 3 notebooks algebraically

Question

N=p+98 

p=n-98

Answer 1

If you let N = cost of a notebook, and p = cost of a pencil, then we have;

 

N = p + 98

 

6 pencils will cost 6p dollars

 

3 notebooks will cost 3(p + 98) dollars

 

Together, the 6 pencils and 3 notebooks cost 6p + 3(p + 98) = 6p + 3p + 294 = 9p + 294 dollars