I need to solve this in the quadratic formula I just can't solve it

Question

500=2.2v+v2/20

Answer 1

I am assuming that this says:

 

500 = 2.2v + (v²)/20

 

Any quadratic is solved by putting everything on one side of the equal sign.  I would subtract 500 from both sides, then put the right side in "standard" order.

 

0 = (1/20)v² + 2.2v - 500

 

Then I would get rid of the fraction - multiply EVERY TERM by 20 (the denominator of the coefficient on the v²)

 

0 = v² + 44v - 10,000

 

This does not factor easily, so the Quadratic Formula is the best option, or completing the square if you are familiar with that method.

 

Using either method I get -22 ± √2621

 

If I did not interpret your original problem correctly, then disregard this answer.

 

Thanks.

Vicki

 

 

Answer 2

v²/20 + 2.2v -500 = 0   2.2 = 2 2/10 = 22/10 = 11/5

a=1/20, b=11/5, c=-500

v = -11/5 ± √((11/5)² -4(1/20)(-500))

                      2(1/20)

v = -11/5 ±√(121/25 + 100)

 

                   1/10

v = -11/5 ± √2621/25 = -11/5±(√2621)/5

                  1/10                     1/10

Multiply numerator and denominator by 10:

v = -22 ± 2√2621 = -22 ± √2621

               1