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What number is divided by 2, 3, 4 or 5 the remainder is always 1?

What number is divided by 2, 3, 4 or 5 the remainder is always 1. The smallest number with these properties is squared. The result would be:

a.961                 b. 3721                 
c.14641                            d. There is not enough information to tell
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1 Answer

The smallest number with this property is 61, and 61^2 = 3721. The answer is B. I simply multiplied 3*4*5. I didn't multiply by 2 because if a number is divisible by 4, then it is automatically divisible by 2. I came up with 60, and when you add 1 it's 61.