Kenneth S. answered 07/19/17
Tutor
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(62)
Let's cut to the chase: I know this subject & how to teach YOU
There are three unknowns, a, b & c but just two equations. If we let a=10 (integer value & therefore using common logs) then
12 = c +b•log2
10 = c + b•log4
then 2 = b(log2 - log 4) and then you could solve for b but it would not be an integer.
But if a=2, then loga 2 = 1 and loga 4 = 2, so let's try this.
12 = c + b
10 = c + 2b
then -2 = b and c = 14. My solution: (a,b,c) =(2,-2,14)