Ella C.

asked • 06/25/14

Solve tan 2x - cot x = 0

Solve tan 2x - cot x = 0 for the interval [0, 2pi)

Joe F.

tutor
Write tan2x as sin2x/cos2x and cots as cosx/Sinx.
Problem becomes:
2sinxcosx/(cos^2 x - sin^2 x) - cosx/sinx = 0. 
Get a common denominator for this difference,
combine like terms and set numerator to 0. 
This yields cosx(3sin^2 x - cos^2 x) = 0.  Set each factor to 0 and you get pi/2, 3pi/2, pi/6 and 7pi/6 as your answers. 
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03/26/18

2 Answers By Expert Tutors

By:

Kevin C.

tutor
AAARG!  I don't believe I made that mistake.
 
tanx = 1/√3 and x = -1/√3  so x = π/6 in each of the 4 quadrants.  Sorry.
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06/25/14

Joe F.

tutor
Wrong answer. Tan^2(x) should equal 1/3 not 3!!
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03/07/17

Kevin C.

tutor
As I said in my correction above.
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03/09/17

Jim S.

This solution misses two additional solutions: π/2 and 3π/2.  Why did that happen?
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03/25/18

Jim S.

Missing pi/2 and 3pi/2 which are also solutions.
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03/25/18

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