
Arturo O. answered 06/30/17
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See my comment below for an alternative way to solve this, without having to use calculus.


Arturo O.
There is a way to solve this without using calculus. From the geometry of the problem, you have a right triangle of height y, base x, and hypotenuse r.
y = 0.5 miles
r = 1 mile
The angle from the base to the hypotenuse is θ.
θ = sin-1(y/r) = sin-1(0.5/1) = 30°
The helicopter measures a component of the car's speed along the hypotenuse, vr.
vr = 66 mph
But vr is a projection along the hypotenuse of the ground speed vg of the car.
vgcosθ = vr
vg = vr / cosθ = (66 /cos30°) mph ≅ 76.2 mph
The car is moving at 76.2 mph toward the point directly below the helicopter.
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07/01/17
Walter B.
06/30/17