-x^2+70x-600=0

Question

Not sure how to get the answer at all. I have the quadratic formula but I am not sure how to apply it

Answer 1

Multiply both sides of the equation by -1. You get the following equation:

 

x^2 - 70x + 600 = 0

 

Factor the quadratic equation. You get: 

 

(x - 60)(x - 10) = 0

 

x - 60 = 0

 

x = 60

 

x - 10 = 0

 

x = 10

Answer 2

Agree with Muhammad

 

you could also use the equation

 

x = (-b ± sqrt(b²-4*a*c)/(2*a)

 

-x^2+70x-600

ax^2+bx+c

 

a = -1

b = 70

c = -600

 

x = (-b ± sqrt(b^2-4*a*c)/(2*a) = (-70 ± sqrt(70^2-4*(-1)*(-600))/(2*(-1))

 

x = (-70 ± sqrt(4900-2400)/(-2)

 

x = (-70 ± sqrt(2500)/(-2)

 

x = (-70 ± 50)/(-2)

 

x = (-70 + 50)/(-2)  or    x = (-70 - 50)/(-2)

 

x = (-20)/(-2) or x = (-120)/(-2)

 

x = 10 or x = 60