Me M.

asked • 01/13/13# solving systems of equations by substitution: 4x+3y=2 3x-2y=10

Please help me I can't solve this.

## 1 Expert Answer

Mykola V. answered • 01/13/13

Math Tutor - Patient and Experienced

Sorry for being so late on the response. Take one of the equations and solve it for either the x or y variables. Let's take the second equation and solve for the y variable.

3x-2y=10 -> -2y=10-3x -> y=(10-3x)/-2

Now all we do is plug that in for the y variable in the first equation and solve for the x.

4x+3((10-3x)/-2)=2 -> 4x+(30-9x)/-2=2 -> 4x-15+4.5x=2 -> 8.5x-15=2 -> 8.5x=17 -> x=17/8.5. ->

x=2.

From there all you do is plug that in for x in either of the equations to get the y variable.

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Me M.

I need step-by-step please. I'm so lost.

01/13/13