
Subhash K. answered 05/19/14
Maths Problem Solver
A) h(x)= (f?g)(x) h(x)= f(g(x))=f(5x-5)=5(5x-5)^2 +8(5x-5) domain= (-infinite, + infinite) B) h(x)=(g?f)(x) h(x)=g(f(x))=g(5x^2 +8x)=5(5x^2 +8x) - 5 domain=(-infinite, + infinite) C) h(x)=(f?f)(x) h(x)= f(f(x))= f(5x^2+8x)=5(5x^2+8x)^2 +8(5x^2+8x) domain=(-infinite, + infinite) D) h(x)=(g?g)(x) h(x)= g(g(x))=g(5x-5)=5(5x-5) -5 domain=(-infinite, + infinite), each value of x that defines the above function h(x)