Michael A. answered 06/09/17
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we know that distance = rate x time
walking, the distance is 3 mi, and we can say that her rate is x miles , and the time it takes to walk is t hours
cycling, the distance is still 3 mi, but now her speed is (x + 4), and the time it takes is (2 - t) hours
Now, let's substitute into our formula for the distance.
Equation 1 is 3 = xt
Equation 2 is 3 = (x + 4)(2 - t)
We can solve the first equation for t
t = 3/x
Now, plug this value of t into the second equation
3 = (x + 4)(2 - 3/x)
3 = 2x - 3 + 8 - 12/x
3 = 2x + 5 - 12/x
3x = 2x² + 5x - 12
2x² + 2x - 12 = 0
x² + x - 6 = 0
(x - 2)(x + 3) = 0
x = 2 and x = -3
The only logical solution is x = 2 because x cannot be negative
Therefore, Melissa's walking speed is 2 mph