1) 15 degrees = 45 degrees - 30 degrees, so use the tangent difference-of-two-angles identity:
tan(u)-tan(v)
tan(u-v) = -------------------
1+tan(u)tan(v)
where u = 45o and v = 30o. We know that tan(45o) = 1 and tan(30o) = 1/√3.
2) cos(105o) = cos(90o+15o) = -sin(15o). Use the sine difference-of-two-angles identity:
-sin(45o-30o) = sin(30o)cos(45o)-sin(45o)cos(30o) [Note that the - sign (-sin(15o)) reverses the usual order]
Where sin(45o)=cos(45o)=1/√2, sin(30o)=1/2, cos(30o)=√3/2.
[105o is also = 60o+45o, so you could also use the cosine sum-of-two-angles identity]