
Philip P. answered 05/03/14
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a) h = (1/2)gt2 + v0t + h0
Where g = the acceleration due to gravity = -32 ft/s2, v0 = the initial velocity = -20 ft/s, h0 = the initial height = 60 feet
h = -16t2 -20t + 60
b) h=0 when the balloon hits the ground, so:
0 = -16t2 -20t + 60
Solve for t (use the quadratic formula)
c) Plug t=0.5 into h = -16t2-20t+60 to get the answer.