Solve √3x^{2} - √2x +3√3=0.
Use the quadratic equation to solve this equation:
x = -b + square root of (b^{2} - 4ac) divided by 2a where a = radical 3, b = -radical 2, and c = 3 radical 3
If you plug in all these values in the quadratic equation you will get the following answer:
x = (radical 2 + radical of -34) divided by 2 radical 3
radical of -1 equals i (imaginary number)
Therefore x = (radical 2 + i radical of 34) divided by 2 radical 3.