Meg,
Let Te be the equilibrium temperature of all three bodies
So the energy given up by the hot copper block (.265*390*(235-Te)) has to be equal to the energy gained by the cup and the water which is (.145*900*(Te-12) +.875*4186*(Te-12)) if energy is to be conserved.
Doing all the arithmetic I get 103.35*(235-Te)=3793.25*(Te-12) from this if you solve for Te I got Te=17.91 deg C.
You can see from the equation above that the water absorbs most of the heat.
Regards
Jim
Leigh A.
04/25/14