After leaving the runway, a plane's angle of ascent is 15 degrees and its speed is 272 feet per second. How many minutes will it takefor the airplane to climb t

Question

After leaving the runway, a plane's angle of ascent is 15 degrees and its speed is 272 feet per second. How many minutes will it takefor the airplane to climb to a height of 14,000 feet? Round anwer to two decimal places.

Answer 1

The slant height =

 

14000/sin(15)

 

=54095 feet

 

Time = 54095/(272*60)

        = 3.31 minutes

 

 

Answer 2

You need to use trigonometry concepts and physics concepts here:

 

1) Physics - the vertical and horizontal problems are totally independent.

     All we care about here is the rate of vertical climb. Rate_v or V_v

 

2)  Find this by trigonometry.

     The Y component (or vertical component) of the rate of climb is based

         on the sine of the angle.  Draw a triangle to show this.

     V_v = sine(15⁰) 272 ft/s =         <<I will let you can calculate this out>>

 

3) Now just solve a standard motion problem in the Vertical direction.

     V_v = D_v / T   => T = D_v / V_v     <<I will let you can calculate this out>>

 

4) Now just change seconds to minutes using 1 min = 60 s