A 10 KG mass rests on a horizontal frictionless surface. A horizontal force of 5 N is applied. After one second, the velocity of the mass

Question

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Answer 1

Answer:  0.5 m/s

 

First step is to draw a free-body diagram, pick a coordinator system, and label all of the forces acting upon the mass.  From the free-body diagram (where x-direction is positive in direction of the horizontal force and y-direction is positive in the opposite direction of gravity), you will see that you only have three forces acting on the mass:  (1) force of gravity in the negative y-direction; (2) normal force in the positive y-direction; and (3) the horizontal force in positive x-direction.

 

With the proper set up, we can now proceed to solve the problem.  From the free-body diagram, we know that the mass is not accelerating in the y-direction because the normal force and the force of gravity cancel each other out.  Therefore, the mass does not have a velocity in the y-direction.

 

In the x-direction, the mass is accelerating because of a net force is applied to the mass.  Using ∑F=ma_x, we can calculate the acceleration in the x-direction, a_x.  Since there is only one force in the x-direction, we only use the horizontal force.  Knowing a_x, we plug a_x into v =v_o + a_xt to find the velocity v.  (Note: v_o = 0 because the mass is initial at rest)

 

Work:

a_x = F/m

a_x = (5 N)/(10 kg) = 0.5 m/s²

 

v =v_o + a_xt

v = 0 + (0.5 m/s²)(1 s) = 0.5 m/s²

Answer 2

what is the question?  is the question the following:  after one second, what is the velocity of the 10kg mass?  if this is

 

the question, then:

 

F = ma ---> 5 = 10a ---> a = 0.5 meters/sec^2;  

 

in which case, assuming initial velocity to be zero:  v(1) = at = 0.5(1) = 0.5 meters/second

 

if this is not the question, then (again) what is the question?