(8x3+16x2+6x)/2x
= (8x3/2x) + (16x2/2x) + (6x/2x)
= 4x2 + 8x + 3 for all x ≠ 0
Sam P.
asked • 04/05/14Divide polynomials using factoring
(8x3+16x2+6x)/2x
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Arthur D. answered • 04/05/14
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(8x^3+16x^2+6x)/(2x)
(8x^3/2x)+(16x^2/2x)+(6x/2x)
4x^2+8x+3
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