Steve S. answered 04/04/14
Tutor
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(3)
Tutoring in Precalculus, Trig, and Differential Calculus
Graph these polar equations using Geogebra:
1)r=-pi/4
2)r=2(1-sin(θ))
It's not hard to generate polar plots in GeoGebra; but they are not native, so there is no direct support.
The technique is to define an angle, say θ, as a number/slider. In the input field type θ = pi, enter. Open the properties of θ and change starting value to 0, ending value to 2 pi, and animation to Increasing. Show the slider.
Type r = (some expression) in input field; enter.
Type P = (r cos(θ), r sin(θ)) in input field; enter.
Find Locus tool (4th tool in tool-bar, last item in list), click to select it, then click on P then on θ. A graph will appear of all possible locations of P for any value of the θ slider.
To see where the point is at any particular value of θ simply drag the slider. To watch it automatically go through all values, turn on animation of θ.
The grid can be changed to polar.
Here’s a GeoGebra file: http://www.wyzant.com/resources/files/268188/polar_technique_in_geogebra
For a quick look, here’s a GeoGebra generated animated gif: http://www.wyzant.com/resources/files/268189/polar_technique_in_geogebra_animated_gif
1)r=-pi/4
2)r=2(1-sin(θ))
It's not hard to generate polar plots in GeoGebra; but they are not native, so there is no direct support.
The technique is to define an angle, say θ, as a number/slider. In the input field type θ = pi, enter. Open the properties of θ and change starting value to 0, ending value to 2 pi, and animation to Increasing. Show the slider.
Type r = (some expression) in input field; enter.
Type P = (r cos(θ), r sin(θ)) in input field; enter.
Find Locus tool (4th tool in tool-bar, last item in list), click to select it, then click on P then on θ. A graph will appear of all possible locations of P for any value of the θ slider.
To see where the point is at any particular value of θ simply drag the slider. To watch it automatically go through all values, turn on animation of θ.
The grid can be changed to polar.
Here’s a GeoGebra file: http://www.wyzant.com/resources/files/268188/polar_technique_in_geogebra
For a quick look, here’s a GeoGebra generated animated gif: http://www.wyzant.com/resources/files/268189/polar_technique_in_geogebra_animated_gif
Steve S.
That's the actual GeoGebra program file (ggb). You have to download it and run it with GeoGebra on your computer.
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04/08/14
Daisy R.
am comfuse
does the file http://www.wyzant.com/resources/files/268188/polar_technique_in_geogebra is only for r=-pi/4
or did you draw both equation together ???
THANK YOU
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04/17/14
Daisy R.
WHY DID I HAVE TO USE THETA FOR r=-pi/4 because i think -pi/4 is independent of theta?
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04/17/14
Steve S.
I drew both equations on the same plane. r = pi/4 is the circle; it has constant radius for all theta angles. r = pi/4 is sort-of the polar equivalent to y = pi/4. In both cases the value is the same for ANY value of the independent variable (theta and
x, respectively).
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04/17/14
Daisy R.
Ooooooooooooh now i got it thank you
:)
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04/18/14
Daisy R.
04/08/14