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Point slope form slope = 5 passing through (-3,4)

I don't know how to do this at all
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3 Answers

point slope form is: (y-y1) = m(x-x1) where m is slope and the point they give you is (x1, y1)
 
1. First plug in
y - 4 = 5(x - (-3))
 
2. Subtracting a negative makes a positive so fix equation
 
y - 4 = 5(x + 3)
 
3. If you need to put it in slope intercept form:
 
y - 4 = 5(x + 3)  (then distribute the 5 to x + 3)
y - 4 = 5x + 15
y - 4 + 4 = 5x + 15 + 4 (add 4 to both sides to get y by itself)
y = 5x + 19
Graph the line with slope 3  passing through the point (-5, 4)
... or m = 5, y = 4,  x = -3
 
y = mx + b
 
4 = 5(-3) + b
 
4 = -15 + b
 
Add 15 to both sides, giving b = 19;   Since y = mx + b: y = 5x + 19